Question

solve this plz
Find the resistance by formula in these ​

Answer 1

Answer:

R=3+3+6=12 ohm is the answer

Answer 2

ANSWER:

(Refer attachment for circuit)

Concept Used:

• We know that, in a circuit if the resistors connected are in series, their equivalent resistance will be : R(eq) = R1 + R2 + . . . . + R(n)
• We know that, in a circuit if the resistors connected are in parallel, their equivalent resistance will be : 1/R(eq) = 1/R1 + 1/R2 + . . . . + 1/R(n)

Solution:

Here, we need to find the equivalent resistance of the given circuit.

We are given,

⇒R1 = 3 ohm

⇒R2 = 3 ohm

⇒R3 = 6 ohm

We can observe that, R1 and R2 are connected in series and R3 is parallel to them.

So, equivalent resistance of R1 and R2:

⇒R(eq) = R1 + R2

⇒R(eq) = 3 ohm + 3 ohm

⇒R(eq) = 6 ohm

Now, we can observe that, R3 and R(eq) will be connected in parallel.

So, equivalent resistance of R3 and R(eq):

⇒1/R'(eq) = 1/R1 + 1/R2 + . . . . + 1/R(n)

⇒1/R'(eq) = 1/R3 + 1/R(eq)

⇒1/R'(eq) = 1/6 ohm + 1/6 ohm

⇒1/R'(eq) = 2/6 ohm

⇒1/R'(eq) = 1/3 ohm

⇒R'(eq) = 3 ohm

So, the equivalent resistance of the given circuit is 3 ohm.

Formulae Used:

• (Series)Equivalent Resistance => R(eq) = R1 + R2 + . . . . + R(n)
• (Parallel)Equivalent Resistance => 1/R(eq) = 1/R1 + 1/R2 + . . . . + 1/R(n)

Definitions:

• Series Connection: Components are connected end-to-end in a line to form a single path through which current can flow:
• Parallel Connection: Components are connected across each other’s leads.