Question

Solve this plz

for all x^2 , x^2 + 2ax +(10-3a) >0 , then the interval in which 'a' lies is ?​​

Answer 1

Ax² + bx + c >0 for all values of x only if

a>0 and D<0

Find discriminate :-

Use this D=b²-4ac

x² -4(10-3a) < 0

4(a² +3a -10) <0

(a+5)(a-2) <0

So a belongs to (-5,2)

Hope it helps you ❤

Answer 2

HEY MATE YOUR ANSWER TO THIS QUESTION IS HERE TO

$a {}^{2} + bx + c$

find

so a belongs to c ( -5,2)