Question

solve this plz the question is in attachment​

Answer 1

I will solve both the questions,

Question 1:

As you can see in the above image that I have uploaded,

Now point E can be above the line segment CB or below the line segment CB.

And we can clearly see that that the Area of ∆ DCE is one forth of the ∆ ABC.

So Area of ∆ ABC = 4 x Area of ∆ CDE.

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Question 2:

$as \: (x + 1) \: and \: (x + 2) \:$
divides the given equation so it will satisfy the equation.

placing x = -1 and x = -2
we will get,

$- a + b - c + d = 0$
and
$- 8a + 4b - 2c + d = 0$
Solving this two we will get,

$6a - 2b + d = 0$