Question

solve this plzz 9 one

Answer 1

if x+1 is factor of this p(x)
zero of the polynomial will be:-
x+1=0
x=1
b(-1)³+(-1)²-2(-1)+4b-9=0
-b+1+2+4b-9=0
3b=6
b=2

Answer 2

$heya \: mate \\ here \: is \: your \: answer \\ \\ p(x) = x + 1 \\ x + 1 = 0 \\ x = - 1 \\ g(x) = bx^{3} + x ^{2} - 2x + 4b - 9 \\ putting \: the \: value \: of \: x \: in \: this \: \\ equation \\ b( -1 ) ^{3} + ( - 1) ^{2} - 2( -1 ) + 4b - 9 \\ \\ - b + 1 + 2 + 4b - 9 \\ = 4b - b - 9 + 3 \\ = 3b - 6 = 0 \\ 3b = 6 \\b = \frac{6}{3} = 2 \\ b = 2$