solve this plzz (after sq of smaller no it is 8times....)
Attachments:
Answers
Answered by
0
Let the 2 no.s be x and y,and x>y
So according to question
x²-y²=180. (1)
also, square of smaller no. is 8 times the larger one
so,y²=8x
or,y=√(8x) (2)
putting the value of y in equation (1) we get
x²-(√8x)²=180
or,x²-8x-180=0
or,x²+10x-18x-180=0
or,x(x+10)-18(x+10)=0
or,(x-18)(x+10)=0
x=-10 or x=18
neglecting the negative value as it contradicts equation 2.
putting x=18 in equation (2) we get y=√(18 x8)=12
So according to question
x²-y²=180. (1)
also, square of smaller no. is 8 times the larger one
so,y²=8x
or,y=√(8x) (2)
putting the value of y in equation (1) we get
x²-(√8x)²=180
or,x²-8x-180=0
or,x²+10x-18x-180=0
or,x(x+10)-18(x+10)=0
or,(x-18)(x+10)=0
x=-10 or x=18
neglecting the negative value as it contradicts equation 2.
putting x=18 in equation (2) we get y=√(18 x8)=12
Similar questions