Math, asked by piyushkumarsin98, 9 months ago

solve this plzz it's urgent​

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Answered by arunyadav1973
1

Answer

Let cost of book be x

If price is increased by 20%

x \times  \frac{20}{100}  \\  = x \times  \frac{1}{5}  \\  =  \frac{x}{5} \\ new \: price \: of \: book \\ x +  \frac{x}{5}  \\  =  \frac{5x + x}{5}  \\  =  \frac{6x}{5}

But price reduced by 20%

 \frac{6x}{5}  \times  \frac{20}{100}  \\  =  \frac{6x}{5}  \times  \frac{1}{5}  \\  =  \frac{6x}{25}  \\ the \: new \: price \: becomes \\  \frac{6x}{5}  +  \frac{6x}{25}  =  \frac{36x}{25}

Compare to original price & new price

x <  \frac{36}{25}

He gains profit

profit \:  = selling \: price - cost \: price \\  =  \frac{36x}{25}  - x \\  =  \frac{36x - 25x}{25}  \\  =  \frac{11x}{25}

profit \: percentage =  \frac{11x}{25}  \times 100 \\  = 44\%

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Answered by Niharikamishra24
1

Answer:

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