Chemistry, asked by hzuaiai, 11 months ago

Solve This Plzzz....​

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Answered by Anonymous
7

Hope This Will Help Uh✌

#_Brōkēn_Hēart☹️

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Answered by krishtiwari07
1

Mass of the Oxygen given = 64 g.

Molar Mass of the Oxygen(O₂) = 32 g/mole.

[2 × 16 = 32]

∴ No. of moles = Mass/Molar Mass.

∴ No. of moles of O₂ = Mass/Molar Mass.

∴ No. of moles of O₂ = 64/32

No. of moles of Oxygen = 2 moles.

Now, Total number of moles in the cylinder = No. of moles of Ne + No. of moles of O₂

= 3 + 2

= 5 moles.

We know,

Partial Pressure of the Oxygen in the Cylinder = Mole Fraction of the Oxygen in the Cylinder.

= Moles of Oxygen/Total Number of moles in the Cylinder.

= 2/5

= 0.4.

Hence, the Partial Pressure of the Oxygen in the cylinder is 0.4.

Hope it helps.

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