Solve this plzzz guys
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AB=AC (given)
BD=CD (given)
AD=AD (common)
∆ABD=~∆ACD (SSS)
angleBAD=angle CAD (CPCT)
angle BDA=angle CAD (CPCT)
Hence proved
BD=CD (given)
AD=AD (common)
∆ABD=~∆ACD (SSS)
angleBAD=angle CAD (CPCT)
angle BDA=angle CAD (CPCT)
Hence proved
pooja6786:
thanks for response
ur wlcm
Answered by
0
It can be proved by proving the congurency of tri.ABD and tri. ADC
AB = AC given
BD = DC given
and AD=AD common
hence by sss cong.
threfore, angle BAD = angle CAD by cpct
may be this is right but I am not sure u must verify it.
AB = AC given
BD = DC given
and AD=AD common
hence by sss cong.
threfore, angle BAD = angle CAD by cpct
may be this is right but I am not sure u must verify it.
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