solve this plzzzz...A paper is in the form of a rectangle ABCD in which AB=20cm andBC=14cm.A semi-circular portion with BC as diameter is cut off.Find the area of the remaining part
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Tan 20
you find the area of your own
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area of rectangular paper = (length x breadth)
= 20 x 14
= 280 sq cm
area of semicircle = (πr^2)/2
r = 14/2 = 7 cm
area = 22/7 x 7^2 / 2
= 154 / 2
= 77 sq cm
area of remaining part = area of rectangle - area of circle
= 280 - 77
= 203 sq cm
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