Question

solve this plzzzz only question 2​

Answer 1

Answer:

k = 6 is the answer.

Step-by-step explanation:

✔If x - 1 is a factor of p (x) = x^3 - kx^2 + 11x -6 then,

✔p (1) = 0.(by factor theorem)

✔p(x) = x^3 - kx^2 + 11x - 6

✔p(1) = 1^3 - k X 1^2 + 11 X 1 - 6

✔p(1) = 0

So,

➡1 - k + 11 -6 = 0

➡12 - 6 - k = 0

➡6 - k = 0

➡-k = -6

k = 6

Answer 2

x-1=0

x=1

Now,put x=1

x^3-kx^2+11x-6=0

(1)^3-k(1)^2+11×1-6=0

1-k+11-6=0

12-6-k=0

6-k=0

-k=-6

k=6

hope this will helps yu