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x^2+1/9x^2 = 25/36
(x)^2 +(1/3x)^2 =25/36
Add 2*(x)(1/3x)= 2/3 both side
(x)^2 +(1/3x)^2+2/3 =25/36+2/3
{(x)+(1/3x)}^2 =25/36 +24/36 =49/36 =(7/6)^2
Taking sqrt
{(x)+(1/3x)} =(7/6)
cubing both sides
{(x)+(1/3x)}^3 =(7/6)^3
(x)^3+(1/3x)^3 +3(x)(1/3x){7/6) =343/216
(x)^3+(x/3)^3 +3(x)(1/3x){7/6)} =343/216
(x)^3+(x/3)^3 +{7/6)} =343/216
subtract 7/6 both sides
(x)^3+(x/3)^3 =343/216-7/6 =343/216 -252/216 =91/216
Hence x)^3+(x/3)^3 = 91/216 .............Ans
(x)^2 +(1/3x)^2 =25/36
Add 2*(x)(1/3x)= 2/3 both side
(x)^2 +(1/3x)^2+2/3 =25/36+2/3
{(x)+(1/3x)}^2 =25/36 +24/36 =49/36 =(7/6)^2
Taking sqrt
{(x)+(1/3x)} =(7/6)
cubing both sides
{(x)+(1/3x)}^3 =(7/6)^3
(x)^3+(1/3x)^3 +3(x)(1/3x){7/6) =343/216
(x)^3+(x/3)^3 +3(x)(1/3x){7/6)} =343/216
(x)^3+(x/3)^3 +{7/6)} =343/216
subtract 7/6 both sides
(x)^3+(x/3)^3 =343/216-7/6 =343/216 -252/216 =91/216
Hence x)^3+(x/3)^3 = 91/216 .............Ans
sparsaparlarpbwkdi:
wrong
ok
x² + (1/9x)² = 25/36
(x + (1/3x))² - 2/3 = 25/36
(x + (1/3x))² = 25/36 + 2/3
(x + (1/3x))² = 49/36
x + (1/3x) = 7/6
6x² - 7x + 2 = 0
x = 1/2, x = 2/3
In both cases
x³+1/(27x³) = 91/216
(x + (1/3x))² - 2/3 = 25/36
(x + (1/3x))² = 25/36 + 2/3
(x + (1/3x))² = 49/36
x + (1/3x) = 7/6
6x² - 7x + 2 = 0
x = 1/2, x = 2/3
In both cases
x³+1/(27x³) = 91/216
its all wrong dont listen to her
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