solve this polynomial
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→(xy-8)[(xy)^2 + 8^2 + 8xy]
→(xy-8)[x^2y^2 + 64 + 8xy]
→(xy-8)[x^2y^2 + 64 + 8xy]
cristianoronaldo1:
uppara abhi kpi ur bhi answer de raha ha
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x^2 y^2+8xy+ 64
how do we get this 512 is a cube of 8
x^3 is the cube of x^1
y ^3 is the cube of y^1
theory a difference of two perfect cubes,a^3 -b^3 can be factored into [a-b] =[a^2+ab+b^2]
how do we get this 512 is a cube of 8
x^3 is the cube of x^1
y ^3 is the cube of y^1
theory a difference of two perfect cubes,a^3 -b^3 can be factored into [a-b] =[a^2+ab+b^2]
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