Math, asked by cristianoronaldo1, 1 year ago

solve this polynomial

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Answers

Answered by Stark5
0
→(xy-8)[(xy)^2 + 8^2 + 8xy]
→(xy-8)[x^2y^2 + 64 + 8xy]

cristianoronaldo1: uppara abhi kpi ur bhi answer de raha ha
k2w2: yy
k2w2: i gave the whole solution
k2w2: with satisfaction
k2w2: and how i got the answer
cristianoronaldo1: marked
cristianoronaldo1: thx bhai
Answered by k2w2
0
x^2 y^2+8xy+ 64
how do we get this 512 is a cube of 8
x^3 is the cube of x^1
y ^3 is the cube of y^1
theory a difference of two perfect cubes,a^3 -b^3 can be factored into [a-b] =[a^2+ab+b^2]
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