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Answered by
1
Answer:
12 m/s^2
Explanation:
Differentiate x=2-5t+6t^2 wrt t
v=-5+12t
Again differentiate v=-5+12t
a=12
Hence acceleration is constant=12..
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Answered by
1
Answer:
(2) 12m/s²
Explanation:
x=6t²-5t+2
dx/dt=velocity,v
d(6t²-5t+2)/dt
=2*6t-5+0
=12t-5
dv/dt
=d(12t-5)/dt
=12-0
=12
therefore initial acceleration=
12m/s²
therefore (2) option is correct
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