solve this problem
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Answer:
(a2+b2+c2-ab-bc-ac)
Step-by-step explanation:
Since you're solving this problem, you should know this identity:
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ac)
From here, divide (a+b+c) from both sides to get
(a3+b3+c3-3abc)/(a+b+c) = (a2+b2+c2-ab-bc-ac)
And hence your answer is (a2+b2+c2-ab-bc-ac)
Hope it helps
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