Question

solve this problem
(2a+5) (2a-3)​

Answer 1

$\huge{\underline{\tt{QUESTION:-}}}$

Solve :-

(2a + 5) (2a - 3)

$\huge{\underline{\tt{ANSWER:-}}}$

(2a + 5) (2a - 3)

= 2a(2a - 3) +5(2a -3)

= ${4a}^{2}$- 6a + 10a - 15

= ${4a}^{2}$+ 4a - 15

Answer 2

Apply the distributive property by multiplying each term of 2a+52a+5 by each term of 2a-32a−3.

4a^{2}-6a+10a-15

4a

2

−6a+10a−15