Question

solve this problem , (-3÷√2-2√2) . i will mark u brainlist

Answer 1

Answer:

Step-by-step explanation:

-3÷(√2-2√2)

-3/(√2-2√2)

= By rationalising(matlab numerator aur denominator ko same no. se multiply karna jiska sign denominator se opposite ho  )    it by(√2 +2√2)

=-3 (√2+2√2)/(√2-2√2)(√2+2√2)

= (-3√2 -6√2)/(√2)²-(2√2)²   [using (a+b)(a-b)=a²-b²]

= (-3√2-6√2)/(2-8)

=(-3√2-6√2)/(-6)

=(3√2+6√2)/6

=3(√2+2√2)/6

 = (√2+2√2)/2

please mark as brainliest