Question

solve this problem
(3+2i)/2-3i)+(3-2i)/(2+3i)​

Answer 1

Answer:

$(\frac{3 + 2i}{2 - 3i}) + ( \frac{3 - 2i}{2 + 3i} ) \\ = \frac{(3 + 2i)(2 + 3i) + (3 - 2i)(2 - 3i)}{(2 - 3i)(2 + 3i)} \\ = \frac{3(2 + 3i) + 2i(2 + 3i) + 3(2 - 3i) - 2i(2 - 3i)}{ {2}^{2} - (3i) {}^{2} } \\ = \frac{6 + 9i + 4i + 6 {i}^{2} + 6 - 9i - 4i + 6 {i}^{2} }{4 - ( - 9)} \\ = \frac{6 + 6 + 6 {i}^{2} + 6 {i}^{2} }{4 + 9} \\ = \frac{12 - 12}{13} = 0 \\ \\ \\ \\ \\ < < < i = \sqrt{ - 1} > > > \\ < < < {i}^{2} = - 1 > >$