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Step-by-step explanation:
A2 =2 and A7=22and n=35
we know that,
A2= a+b=2...(i)
and A7=a+6d=22...(ii)
solving the linear equation (i)and(ii), we get
a+d-a-6d=2-22
=-5d=-20
d=4
putting the value of d in equation (i) we get
a+4=2
=a=2-4=-2
now,we have to find the sum of first 35 terms
Sn = n\2(2a+(n-1)d)
S35=35\2[2×(-2)+(35-1)4]
S35 = 35\2[-4+34×5]
S35=35[-2+34×2]
S35=35[66]
S35=2210
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