Math, asked by BazalledBlue, 13 days ago

solve this problem...​

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Answers

Answered by ProximaNova
3

Answer:

x = 1, y = 1

Step-by-step explanation:

For solving these equations,

let 1/(3x + 2y) = a , 1/(3x - 2y) = b

Thus the equations become,

2a + 3b = 17/5 ...(i)

5a + b = 2 ...(ii)

Multiplying (ii) by 2/5 ,

2a + 2b/5 = 4/5 .. (iii)

Now (i) - (iii) :

3b - 2b/5 = 13/5

13b/5 = 13/5

b = 1

So, a = 1/5

Now,

1/(3x + 2y) = 1/5 , 3x + 2y = 5

1/(3x - 2y) = 1 , 3x - 2y = 1

Adding these two,

6x = 6

x = 1

Putring x = 1,

y = 1

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