Question

Solve this problem................

Answer 1

In ABD and BAC

AD=BC (given)

angleBAD=angleBAC(given)

AB=AB (common)

Triangle ABD CONGURENT TO triangleBAC

BY SAS CONGURENCY

Answer 2

Given,
AD=BC
angle DAB = Angle CBA

i) in ∆ABD & ∆BAC
AD=BC
angle DAB = Angle CBA
AB=AB (COMMON)

∆ABD ~ ∆BAC (BY SAS)

ii) BD=AC (CPCT)

iii) ANGLE ABD = ANGLE BAC ( CPCT)

hope this may help