Math, asked by Anonymous, 1 year ago

SOLVE THIS PROBLEM......






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Answered by Anonymous
8

11^x = 3^y = 99^z

99^z = (11× 9)^z = (11× 3^2)^z = 11^z 3^2z

So 11^x = 11^z 3^2z = 3^y

11^x = 11^z 3^ 2z

11^( x-z) = 3^2z

11^( x- z)/2z = 3

Also 11^x = 3^y

11^x/y = 3

11^x/y = 11^( x- z)/2z

x/y = x- z)/2z

2zx = yx - yz

2zx + yz = yx

yx - yz - zx = zx

yx-( yz + zx) = zx

yz + zx = yx - zx

1/x + 1/y + 1/z

yz + zx + xy)/ xyz

yx - zx + xy)/ xyz

2yx - zx)/ xyz

2y - z)/ yz

2/z - 1/y

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