Question

solve this problem ​

Answer 1

Answer:

Step-by-step explanation:

$let \;the\; angles\; be\\ \\\theta_1\;and\theta_2\\\\tan\theta_1 =3\\\\tan\theta_2 =2\\\\tan(\theta_1-\theta_2)=|\frac{tan\theta_1-tan\theta_2}{1+tan\theta_1tan\theta_2}|\\\\tan(\theta_1-\theta_2)=\frac{3-2}{1+6}\\\\tan(\theta_1-\theta_2)=\frac{1}{7}\\\\Sin(\theta_1-\theta_2)=\frac{1}{5\sqrt{2}}\\\\Cos(\theta_1-\theta_2)=\frac{7}{5\sqrt{2}}\\\\Now \\\\Sin2(\theta_1-\theta_2)=2Sin(\theta_1-\theta_2)Cos(\theta_1-\theta_2)\\\\Sin2(\theta_1-\theta_2)=\frac{14}{50}=\frac{7}{25}$

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