SOLVE THIS PROBLEM
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Answer it.........
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shobhitsharma0:
it,s answer is 0
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0
Answer:
0
Step-by-step explanation:
2^x=3^y=6^-z=k
x=log2(k)
y=log3(k)
z=log1/6(k)
2,3,1/6 is the base
1/x+1/y+1/z=logk(2)+logk(3)+logk(1/6) k is the base
=logk(2×3/6)
=logk(1)
=0
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