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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
Solution :-
Number of students who took English = 18
n(E) = 18
Number of students who took Hindi = 23
n(H) = 23
Number of students who took Maths = 24
n(M) = 24
Number of students who took Hindi and Maths
=n(H n M) = 13
Number of students who took English and Hindi = n (E n H) = 12
Number of students who took English and Maths
= n ( E n M) = 11
Number of students who took all the three subjects = n ( H n E n M) = 6
On covering the above data into Venn-diagram
See the above attachment
1) Total number of students in the clss XI =n(HUEUM)
We know that
n(AUBUC) = n(A)+n(B)+n(C)-n(AnB)-n(BnC)-n(CnA)+n(AnBnC)
On applying this formula to above data
=> n(HUEUM) = n(H)+n(E)+n(M)- n(HnE)- n(EnM)- n(MnH)+n(HnEnM)
=> 23+18+24-12-11-13+6
=> 71-36
=> 35
Therefore, n(HUEUM) = 35
2)Number of students who took Maths not Hindi
= 5+6 = 11
3)Number of students exactly who took one of the three subjects
Only Maths = 6
Only Hindi = 4
Only English = 1
Total = 6+4+1 = 11
3)Number of students exactly who took two of the three subjects
Maths and English = 5
Hindi and Maths = 7
Hindi and English = 6
Total = 5+6+7 = 18