Math, asked by Anonymous, 1 day ago

Solve this problem ASAP ​

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Answered by samipan5050
0

Answer:

you can get a good night's sleep and I will talk to you later

Step-by-step explanation:

you can get a good night's sleep and I will talk to you later

okay thanks for getting back with me so I can get my

Answered by tennetiraj86
2

Step-by-step explanation:

Solution :-

Number of students who took English = 18

n(E) = 18

Number of students who took Hindi = 23

n(H) = 23

Number of students who took Maths = 24

n(M) = 24

Number of students who took Hindi and Maths

=n(H n M) = 13

Number of students who took English and Hindi = n (E n H) = 12

Number of students who took English and Maths

= n ( E n M) = 11

Number of students who took all the three subjects = n ( H n E n M) = 6

On covering the above data into Venn-diagram

See the above attachment

1) Total number of students in the clss XI =n(HUEUM)

We know that

n(AUBUC) = n(A)+n(B)+n(C)-n(AnB)-n(BnC)-n(CnA)+n(AnBnC)

On applying this formula to above data

=> n(HUEUM) = n(H)+n(E)+n(M)- n(HnE)- n(EnM)- n(MnH)+n(HnEnM)

=> 23+18+24-12-11-13+6

=> 71-36

=> 35

Therefore, n(HUEUM) = 35

2)Number of students who took Maths not Hindi

= 5+6 = 11

3)Number of students exactly who took one of the three subjects

Only Maths = 6

Only Hindi = 4

Only English = 1

Total = 6+4+1 = 11

3)Number of students exactly who took two of the three subjects

Maths and English = 5

Hindi and Maths = 7

Hindi and English = 6

Total = 5+6+7 = 18

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