Math, asked by Anuragkkumar2006, 15 days ago

solve this problem correctly and get brainy mark
class 10 ch-1 real numbers​

Attachments:

Answers

Answered by Kim0970
1

It is given that there are 32 students in section A and 36 students in section B.

To determine the minimum number of books required to distribute equally among students of section A and section B, we need to find the LCM of 32 and 36.

To find the LCM, we find the prime factors of 32 and 36 as follows:

Prime factors of 32 are 2. Prime factorization of 32 in exponential form is:

32 = {2 ^{5} }

Prime factors of 36 are 2,3. Prime factorization of 36 in exponential form is:

 36 = {2}^{2}  \times {3}^{2}

Now multiplying the highest exponent prime factors to calculate the LCM of 32 and 36, we have:

LCM (32, 36) =

 {2}^{5}  \times  {3}^{2}  = 288

Hence, the minimum number of books required to distribute equally among students of section A and section B are 288.

Similar questions