Question

solve this problem earlier I will givving him or her brainliest ansewr​

Answer 1

Answer:

hi the answer will be

BCD=ACD

BCE = ABC

DCB= ADC

THANK YOU

Step-by-step explanation:

PLEASE MARK BRAINLIEST AS YOU HAVE SAID

Answer 2

AX is the bisector of angle BAC , P is any point on AX. Prove that the perpendiculars drawn from P to AB and AC are equal.

Construction: From X, draw LX⊥AC and XM⊥AB, And, join YC

Proof:

(I) In △AXL and △AXM

∠XAL=∠XAM (Given)

AX=AX (Common)

∠XLA=∠XMA (each 90

o

)

Thus, by ASA criterion of congruence

△AXL≅△AXM

And, by Corresponding Parts of Congruent Triangle (CPCT)

XL=XM

Therefore, X is equidistant from AC and AB

(ii) In △YTA and △YTC

AT=CT (Common)

∠YTA=∠YTC (Each 90

o

)

YT=YT

Thus, by SAS criterion of congruence

△YTA≅△YTC

And, by Corresponding Parts of Congruent Triangle (CPCT)

YA=YC

Therefore, Y is equidistant from A and C