Question

solve this problem fast
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Answer 1

$\huge\underline\bold\pink{Answer}$

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$\huge\underline\bold\orange{Given\: Polynomial}$

$p(y)\:=\:4\:+\:3y\:-\:y^2\:+\:5y^3$

$\huge\underline\bold\blue{To\:Find}$

$\huge\pink{Value\:of\:p\:when\:p\:is\:2\:and\:-1}$

$\huge\underline\bold\green{Solution}$

Let p (y) be 2 then ,

$p(2)\:=4\:+\:3(2)\:-\:2^2\:+\:5(2)^3$

p(2) = 4 + 6 - 4 + 40

p(2) = 46

$\huge\underline\bold\purple{Solution\:2}$

Let p ( y) be -1 then ,

$p(-1)\:=4\:+\:3(-1)\:-\:(-1)^2\:+\:5(-1)^3$

p(-1) = 4 - 3 - 1 - 5

p(-1) = 4 - 9

p(-1) = - 5

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$\huge\underline\bold\red{Thanks}$

Answer 2

Given =》

p(y)= 4+3y-y²+5y³

Need to find =》

p(0) , p(2) , p(-1)

Explanation =》

p(y)= 4+3y-y²+5y³

= 5y³-y²+3y+4

i) putting y = 0

p(0) = 5y³-y²+3y+4

= 5×(0)³-(0)²+3×(0)+4

= 5×0-0+3×0+4

= 0-0+0+4

= 4

ii) putting y = 2

p(2)= 5y³-y²+3y+4

= 5×(2)³-(2)²+3×(2)+4

= 5× 8-4+6+4

= 40-4+6+4

= 50-4

= 46

iii) putting y = -1

p(-1)= 5y³-y²+3y+4

= 5×(-1)³-(-1)²+3×(-1)+4

= 5×(-1)-1-3+4

= -5-1-3+4

= -9+4

= -5

hope IT HELPs u !!!

@Radhika : )