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AB||CD
EF||CD
Therefore, AB||EF (lines parallel to same line are parallel to each other)
x = z (alternate interior angle)
AB||CD
x+y = 180° (co-interior angles are supplementary)
Therefore, x=z
z+y = 180°
given y:z = 3:7
Let y be 3a and z be 7a.
3a + 7a = 180°
10a = 180°
a = 180/10
a = 18
y = 3a = 3×18 = 54°
z = 7a = 7×18 = 126°
x = z = 126°
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