Question

Solve this Problem Fast answer ​

Answer 1

Area: ½ x (product of the lengths of the diagonals)

Perimeter: 4 x side

Number of vertices: 4

Number of edges: 4

Properties: Isotoxal figure, Convex polygon

Type: Parallelogram, Quadrilateral, Kite

Line of symmetry: 2

Answer 2

$\\ \\ \large\underline{ \underline{ \sf{ \red{correct \: question:} }}} \\ \\ \tt \: ( { \frac{4}{11} )}^{x - 1} = { (\frac{11}{4} )}^{2x - 5}$

$\\ \\ \large\underline{ \underline{ \sf{ \red{solution:} }}} \\ \\ \tt \: ({ \frac{4}{11} )}^{x - 1} = { (\frac{11}{4} ) }^{2x - 5} \\ \\ \\ \boxed{ \bf \: \frac{a}{b} = ({ \frac{b}{a} )}^{ - 1} }\\ \\ \\ \tt \: ({ \frac{4}{11} )}^{x - 1} = {( { \frac{4}{11} }^{ - 1}) }^{2x - 5} \\ \\ \\ \boxed{ \bf \: { ({a}^{x} )}^{y} = {a}^{xy} } \\ \\ \\ \tt \: ({ \frac{4}{11} )}^{x - 1} = {( \frac{4}{11}) }^{ - 2x + 5} \\ \\ \\ \sf \: since \: coefficient \: is \: same...so \: power \: will \: be \: same \\ \\ \\ \tt \: x - 1 = - 2x + 5 \\ \\ \\ \tt \: x + 2x = 5 + 1 \\ \\ \\ \tt \: 3x = 6 \\ \\ \\ \boxed{ \bf \pink{\:x = 2 }}$