Question

solve this problem fast answer ​

Answer 1

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${a}^{2} + \frac{ {b}^{2} }{4} + \frac{ {c}^{2} }{9} + ab + \frac{bc}{3} + \frac{2}{3}ca$

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$= > {a}^{2} + \frac{ {b}^{2} }{4} + \frac{ {c}^{2} }{9} + ab + \frac{bc}{3} + \frac{2ac}{3} \\ = > { (a)}^{2} + \frac{b}{ {2}^{2} } + \frac{c}{ {3}^{2} } + 2(a) \frac{b}{2} + 2 \frac{b}{2} \\ = > \frac{c}{3} + 2(a) \frac{c}{3} \\ (a+b/2+c/3)² \\ (a+b/2+c/3)(a+b/2+c/3)$