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Answer:
A = { 2,3 }
B = { 0,1 }
C = { 1,2 }
- LHS : A x ( B
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A×(BnC)=(A×B)n(A×C)=({2,1},{3,1})
Step-by-step explanation:
As per given Data, The sets are
A={2,3} ,B={0,1} and C={1,2}
First consider LHS:A×(BnC)
find,BnC=({0,1},{1,2})={1}
A×(BnC)={2,3}×{1}=({2,1},{3,1})
Consider RHS:(A×B)n(A×C)
(A×B)n(A×C)=({2,0},{2,1},{3,0},{3,1})n({2,1},{2,2},{3,1},{3,2}
(A×B)n(A×C)=({2,1},{3,1})
hence, The value of A×(BnC)=(A×B)n(A×C)=({2,1},{3,1}) and it's proved.
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