Math, asked by richa311, 1 year ago

solve this problem friends

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Answered by Anonymous
0
xy = tan (xy)

let xy = t

dt/dx = y + y' x

So t= tan t

differentiate both sides

1 = sec^2 t

Again differentiate but wrt to x

0 = 2 sec t . sec.t .tant . dt/dx

dt/dx = 0

So substitute dt/dx = y + y'x

y + y'x = 0

y = - y' x

y' = -y/x
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