Question

solve this problem given above​

Answer 1

$\begin{gathered} \boxed { \frac{x}{y} = ( \frac{3}{4} ) {}^{ - 3} \div ( \frac{4}{5} ) {}^{0} } \\ \frac{x}{y} = \frac{4}{3} \div \frac{1}{1 } \\ \frac{x}{y} = \frac{3}{4} \\ \boxed{ \red{ To \: Find \: \: (\frac{x}{y} {})^{ - 2} } = ( \frac{3}{4} ) {}^{ - 2} = (\frac{4}{3} ){}^{2} = \frac{16}{9} }\end{gathered}$

Answer 2

Step-by-step explanation:

x/y = (3/4)-³ ÷ (4/5)⁰

x/y = (4/3)³ ÷ 1

x/y = 64/27

(x/y)-² = (64/27)-²

(x/y)-² = 729/4096