Question

Solve this problem guys

Answer 1

Answer:

assume that the box has a , b, c, d then we get a+b=8, c-d=6, a+c=13, b+d=8 . then solve a+b =8 and a+c=13 . by substituting those two we get

-c-b=5 assume these as eq 1

then similarly solve next two, we get c-b=-2 assume these as eq 2

by solving eq 1 and 2 , we get 2b=3

b=3/2 =1.5

sub b value in a+b=8

a+3/2 =8

a=6.5

similarly sub b value in b+d=8

3/2+d=8

d=6.5

sub a value in a+c=13

13/2+c=13

c=6.5

so, substitute a, b, c, d in your question then you get your required answer

Answer 2

${\boxed{\boxed{\underline{\red{\rm{QUESTION :}}}}}}$

$\rm \: { \boxed{}} \: + { \: \boxed{}} \: = 8 \\ \: \ - \: \: \: \: \: - \\ \: \: { \boxed{}} \: - { \: \boxed{}} = 6 \\ \: \: = \: \: \: \: \: \: = \\ \: \: 13 \: \: \: \: \: \: 8$

${\boxed{\boxed{\underline{\red{\rm{To \: Find :}}}}}}$

The blank space and numbers.

${\boxed{\boxed{\underline{\red{\rm{Assumption:}}}}}}$

$\rm \: { \boxed{a}} \: + { \: \boxed{b}} \: = 8 \\ \: \ - \: \: \: \: \: - \\ \: \: { \boxed{c}} \: - { \: \boxed{d}} = 6 \\ \: \: = \: \: \: \: \: \: = \\ \: \: 13 \: \: \: \: \: \: 8$

${\boxed{\boxed{\underline{\red{\rm{SOLUTION :}}}}}}$

$\leadsto$We have to find the numbers whose sum is 8.

$\leadsto$ So, we have, a+b = 8 , c-d = 6, a+c = 13 or b+d = 8.

$\implies$ As per Assumption,

$\leadsto$ a + b = 8

$\leadsto$ a = 8 - b

$\leadsto$ a + c = 13 ------(1)

$\implies$ put a value in equ.(1)

$\leadsto$ (8-b)+ c = 13

$\leadsto$ 8 - b + c = 13

$\leadsto$ -b + c = 13 -8

$\leadsto$ c = 5+b--------(2)

$\leadsto$ similarly, c-d = 6 --------(3)

$\implies$ put c value in equ. (3)

$\leadsto$ 5+b +d = 6

$\leadsto$ b+d = 6-5

$\leadsto$ b+d = 1

$\leadsto$ .°. b = 1+d -------(4)

$\implies$ Now, we have b+d = 8 .------(5)

$\leadsto$ put b value in equ. (5)

$\leadsto$ 1+d+d = 8

$\leadsto$ 2d = 8-1

$\leadsto$ ${\boxed{d = 3.5}}$

$\implies$ put d value in equ. (3)

$\leadsto$ b = 1+3.5

$\leadsto$ ${\boxed{b = 4.5}}$

$\implies$ put b value in equ. (2)

$\leadsto$ c = 5+ 4.5

$\leadsto$ ${\boxed{<strong> </strong><strong>C</strong><strong> </strong><strong>=</strong><strong> </strong><strong>9</strong><strong>.</strong><strong>5</strong>}}$

$\implies$ put c value in equ. (1)

$\leadsto$ a + 9.5 = 13

$\leadsto$ a = 13-9.5

$\leadsto$ ${\boxed{a = 3.5}}$

_____________

${\boxed{\boxed{\underline{\red{\rm{Since :}}}}}}$

$\rm \: { \boxed{3.5}} \: + { \: \boxed{4.5}} \: = 8 \\ \: \ - \: \: \: \: \: - \\ \: \: { \boxed{9.5}} \: - { \: \boxed{3.5}} = 6 \\ \: \: \: \: \: = \: \: \: \: \: \: \: \: \: \: \: = \\ \: \: 13 \: \: \: \: \: \: \: \: \: \: \: \: \: \: 8 \:$