Question

solve this problem guyzzzzzzzzz ​

Answer 1

Answer:

GIVEN:THE PERIMETER OF TRIANGULAR FIELD =540cm

Let the sides are 25x 17x 12x

PERIMETER OF TRIANGLE=SUM OF TREE SIDES

25x+17x+12x =540

54x=540

x=10

1st side(a) =25x=25×10=250

2nd side (b)=17x=17×10=170

3rd side (c)=12x=12×10=120

semi-perimeter(S) =a+b+c/2

=(250+170+120)/2= 540/2=

area of triangle = √s(s - a)(s - b)(s - c)}}

[BY HERON'S FORMULA]

= √S(S - 250)(S - 170)(S - 120)

= √270(270 - 250)(270 - 170)(270 - 120)

=√270×20×100×150

= √81000000

= ARE OF TRIANAGLE =9000m²

HENCE THE ARE OF TRIANGLE IS= 9000m

HOPE IT HELPS..!!

Answer 2

Answer:

$\pink{9000{cm}^{2}\ is\ answer}$

Refer to above attachment.