solve this problem I mark you as brainliest
Attachments:
Answers
Answered by
1
this is your answer. please mark as BRAINLIEST if helped
Attachments:
Avijith:
if helped please mark BRAINLIEST
wait
Answered by
0
The total addition of all interior angles of a polygon=(n-2)×180 where"n" is the numberbof sides
So for six sides we see..
=(6-2)×180=720°
And according to the question,
two angles are 120°,160° and the other 4 angles are equal and we let them=4x
So,
=120+160+4x=720
=280+4x=720
=4x=720-280
=4x=420
=x=420/4
=x=105°
1st angle=120
2nd angle=160
3rd angle=4x=4×105=420
4th angle=4x=4×105=420
5th angle=4x=4×105=420
6th angle=4x=4×105=420
This is the answer and you can mark it as brainliest you will get points for that..!!!!
So for six sides we see..
=(6-2)×180=720°
And according to the question,
two angles are 120°,160° and the other 4 angles are equal and we let them=4x
So,
=120+160+4x=720
=280+4x=720
=4x=720-280
=4x=420
=x=420/4
=x=105°
1st angle=120
2nd angle=160
3rd angle=4x=4×105=420
4th angle=4x=4×105=420
5th angle=4x=4×105=420
6th angle=4x=4×105=420
This is the answer and you can mark it as brainliest you will get points for that..!!!!
Similar questions