Question

SOLVE THIS PROBLEM
I WILL MARK YOU AS BRAINILEST ​

Answer 1

Types of observations = (1,1);(1,2);(1,3);(1,4);(1,5);(1,6);(2,1);(2,2);(2,3);(2,4);(2,5);(2,6);(3,1);(3,2);(3,3);(3,4);(3,5);(3,6);(4,1);(4,2);(4,3);(4,4);(4,5);(4,6);(5,1);(5,2);(5,3);(5,4);(5,5);(5,6);(6,1);(6,2);(6,3);(6,4);(6,5);(6,6); P(of getting product of two scores as 4)=3/36=1/12; P(Product of two scores as 12)=4/36=1/9

Answer 2

Answer:

total outcomes = 36

the favourable outcome to get score as 4 =3 (1,4) (2,2) (4,1)

the probability of getting score as 4=36/3=12

the favourable outcome to get a score as 12=4 (2,6) (3,4) (4,3) 6,2)

the probability of getting a score as 12=36/4=9