solve this problem its urgent
Sorry for blur image
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Answer:
→ (-3)² * (-3)⁻⁶
a⁻ⁿ = 1/aⁿ
→ (-3)² * 1(-3)⁶
→ (-3)²/(-3)⁶
bᵃˣ = (bᵃ)ˣ
→ (-3)²/(-3²)³
→ (-3)²/[(-3)²×(-3)²×(-3)²]
(-3)² cancels from numerator and denominator
→ 1/[(-3)²×(-3)²]
→ 1/(-3²)²
(-3)² = 9 = 3²
→ 1/(3²)²
hence, verified.
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Answer:
Here your answer kookie
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Btw writing is tooooo good
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