Question

solve this problem no. 22​

Answer 1

Explanation:

Let x - y be a.

$2a ^{2} - 9a \: + 10$

$= 2a { }^{2} - 4a - 5a + 10$

$= 2a(a - 2) - 5(a - 2)$

$=(2a - 5)(a - 2)$

$= (2(x - y) - 5)(x - y - 2)$ [substitute value of a]

$= (2x - 2y - 5)(x - y - 2)$

Answer: (2x - 2y -5) (x - y - 2)

Extra explanation:

-9a is divided into -4a and -5a because we need two numbers such that their product is (2) (10) = 20 and their sum is equal to -9. This can be used in most quadratic equations to find the roots.

If this answer helps, it'd be great if it is marked as Brainliest. :D

Answer 2

Answer:

(x+y−5)(2x+2y+1)

Step-by-step explanation:

Let (x+y)=p, then the equation 2(x+y) ²

−9(x+y)−5 becomes 2p²

−9p−5

Consider the expression 2p ²

−9p−5 we can factorise it as follows:

2p ²

−9p−5=2p ²

−10p+p−5=2p(p−5)+1(p−5)=(p−5)(2p+1)

Now, substitute the value of p as p=(x+y):

(p−5)(2p+1)=(x+y−5)(2(x+y)+1)=(x+y−5)(2x+2y+1)

Hence, 2(x+y) ²

−9(x+y)−5=(x+y−5)(2x+2y+1)