Question

solve this problem no. 6

Answer 1

Let the number be y.

so according to question
$\frac{2 \frac{3y}{4} }{3} + \frac{3 \frac{4y}{5} }{4} = xy$
$\frac{6y}{12} + \frac{12y}{20} = xy \\ \frac{1y}{2} + \frac{3y}{5} = xy \\ \frac{11y}{10} = xy$
so
$x = \frac{11}{10}$