Question

Solve this problem please!!​

Answer 1

Answer:

Answer

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR=AS=  

2

6

​  

=3 cm

OR=OS=OM=5 m   [radii of circle]

In △OAR

OA  

2

+AR  

2

=OR  

2

 

OA  

2

+3  

2

=5  

2

 

OA=  

25−9

​  

 

OA=4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS=90  

o

 

RC=CM

Area of △ORS=  

2

1

​  

×OA×RS

2

1

​  

×RC×OS=  

2

1

​  

×4×6

RC×5=24

RC=4.8 m

RM=2RC=2×4.8=9.6 m

So, distance between Reshma and Mandip is 9.6 m

Step-by-step explanation:

Answer 2

Answer:

hoi Hallo

Step-by-step explanation:

how are you

I am fine