solve this problem please
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Note that :
9 exceeds 7 by 2
=> 9 is greater than 7 by 2
=> 9 = 7 + 2
a = first term , d = common difference
As 17th term exceeds its 10th term by 7
=> 17th term is greater than its 10th term by 7
=> a17 = a10 + 7 ------> using note above
=> a + 16d = a + 9d + 7
=> a - a + 16d - 9d = 7
=> 0 + 7d = 7
=> 7d = 7
=> d = 1
Therefore , common difference = 1
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