Math, asked by mohinisoni9055, 3 days ago

solve this problem. please I will mark u brainliest​

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Answers

Answered by aaditambaku
0

first one second

angle axb is 45

angle xab is 85 leaner pair

45+85+angle axb=180

130+angle axb =180

angle axb = 180-130=50

first one first

angle xyp is 65

36+65+angle pxy=180

101+angle pxy=180

angle pxy=180-101=79

PLEAS mark me brainliests

Answered by anilbokefode116
0

Q.1=

|_ RQP= |_XYP

|_RQP = 65'

hence |_XYP =65'

now in ∆XYP

|_XPY + |_PYX + |_PXY = 180'

35' + 65'+|_PXY =180'

|_PXY = 180-100

|_PXY = 80'

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