Question

solve this problem please question n.o 35 and 37​​

Answer 1

Answer:

35.$\frac{1}{16} \times (\frac{1}{2})^{2} = ( \frac{1}{2} )^{3(x - 2)} \\ \frac{1}{16} \times \frac{1}{4} = \frac{1}{64} \\ ( \frac{1}{2} )^{3(x - 2)} = ( \frac{1}{2} )^{3x - 6}$

Now, refer to the 1st and 2nd attachment.

x = 4

$\frac{x - 1}{x + 1} = \frac{4 - 1}{4 + 2} = \frac{3}{6} = \frac{1}{2} = 0.5$

37. Refer to the 3rd attachment.

Hope it helps : )