solve this problem pleaseeeeee
Attachments:
Answers
Answered by
1
take [3x+2y]the whole cube and substitute the values
Answered by
1
Hii
(3x+2y) =9
Cube on both sides,
(3x+2y)³=9³
27x³+8y³+3(3x*2y)(3x+2y) =729
27x³+8y³+12(xy)(9)=729
27x³+8y³+12*3*9=729
27x³+8y³+324=729
27x³+8y³=729-324
27x³+8y³=405
I hope this will help you
(3x+2y) =9
Cube on both sides,
(3x+2y)³=9³
27x³+8y³+3(3x*2y)(3x+2y) =729
27x³+8y³+12(xy)(9)=729
27x³+8y³+12*3*9=729
27x³+8y³+324=729
27x³+8y³=729-324
27x³+8y³=405
I hope this will help you
khushishah2403:
(a+b)^3=a^3+a^2b+b^2a+b^3
Similar questions