Question

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Answer 1

$30. \: \frac{a}{2} - \frac{3a}{4} = 21 - \frac{5a}{6}$

$= > \frac{2a - 3a}{4} = 21 - \frac{5a}{6}$

$= > \frac{ - a}{4} = 21 - \frac{5a}{6}$

$= > \frac{ - a}{4} + \frac{5a}{6} = 21$

$= > \frac{ - 3a + 5a}{6} = 21$

$= > \frac{2a}{6} = 21$

$= > \frac{a}{3} = 21$

$= > a = 21 \times 3$

$= > a = 63$

$31. \: let \: no = x$

$according \: to \: statement$

$(x - \frac{1}{2} ) \times 4 = 5$

$4x - \frac{4}{2} = 5$

$4x - 2 = 5$

$4x = 5 + 2$

$4x = 7$

$x = \frac{7}{4}$

$32. \: x-2x+2 \frac{-16x}{2} = 3 \frac{-7x}{2}$

$\: 2 \frac{2x-4x-16x}{2} = 3 \frac{-7x}{2}$

$\: 2 \frac{-18x}{2} = 3 \frac{-7x}{2}$

$\: 2+3 = \frac{-7x}{2} \frac{+16x}{2}$

$\: 5 = \frac{-7x+16x}{2}$

$\: 5 = \frac{9x}{2}$

$\: 5\times \frac{2}{9} = x$

$\: \frac{10}{9} = x$

$\: x = \frac{10}{9}$

$33. \: y- \frac{y-1}{2} = 1- \frac{y-2}{3}$

$\: \frac{2y-y+1}{2} = \frac{3-y+2}{3}$

$\: \frac{y+1}{2} = \frac{5-y}{3}$

$\: \frac{3y+3}{6} = \frac{10-2y}{6}$

$\: \frac{1}{6}\times(3y+3) = \frac{1}{6}\times(10-2y)$

$\: 3y+3 = 10-2y$

$\: 3y+2y = 10-3$

$\: 5y = 7$

$\: y = \frac{7}{5}$

Answer 2

Answer:

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