solve this problem. Q-(v)
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2(4x - 1) < 4(3x +1)
=> 8x - 2 < 12x + 4
=> 8x -12x < 2 + 4
=> -4x < 6
=> x <
=> x <
=> x < -1.5
Thus, x is any negative integer less than (-1.5).
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