Question

solve this problem????ques. no. 9​

Answer 1

Answer:

GIVEN

AD=BC

<ABC=<BAD=90°

as the above angles are so they can also b called corresponding angles

Hence AD//BC

So <BCD=<ADC. [alternate interior angles]

Therefore. ∆ADO congruent ∆ BCO. [ASA]

So OA=OB

OD=OC

So we can say that CD bisect AB

Answer 2

Answer:

in triangle OBC and OAD

AD=BC (given)

angle A = angle B (90°)

angle AOD= angle BOC (vertically opposite angles)

hence the triangle OBC is congrant to triangle OAD

so the side OA=OB (cpct)

thus we can say CD bisect AB

my pleasure we this is helpful to the readers