Question

solve this problem question

Answer 1

3x²-8x+2k+1 a=3, b=-8 ,c=2k+1
suppose the zeroes of the equation are α and β . by the given condition α=7β
as we know , α+β=-b/a
7β+β=-(-8)/3
8β=8/3
β=8/3×1/8=1/3
αβ=c/a
7β×β=2k+1/3
7×1/3×1/3=2k+1/3
7/9=2k+1/3
21/9=2k+1
21/9-1=2k
12/9=2k
4/3=2k
4/6=k
2/3=k
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Answer 2

Let one zero be x than other is 7x
3x^2-8x+2k+1
X+7x=-b/a
8x=8/3
X=1/3
So
3x(1/3)^2-8x1/3+2k+1=0
1/3-8/3+2k+1=0
1-8+6k+3/3=0
-4+6k=0
K=2/3