solve this problem question no.4
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mummasdollmuski:
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what is this
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Answered by
1
T19 = 52
=> a + 18d = 52 -------(1)
T38 = 128
=> a + 37d = 128 -------(2)
On subtracting equation 1 from 2, we get
19d = 76
=> d = 4
Now,
a + 18(4) = 52
=> a + 72 = 52
=> a = 52 - 72
=> a = - 20
S56 = 56 /2 [ 2(-20) + ( 55)(4)]
= 28 ×( - 40 + 220)
= 28 × 180
= 5040
=> a + 18d = 52 -------(1)
T38 = 128
=> a + 37d = 128 -------(2)
On subtracting equation 1 from 2, we get
19d = 76
=> d = 4
Now,
a + 18(4) = 52
=> a + 72 = 52
=> a = 52 - 72
=> a = - 20
S56 = 56 /2 [ 2(-20) + ( 55)(4)]
= 28 ×( - 40 + 220)
= 28 × 180
= 5040
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Answered by
0
T19 = 52
=> a + 18d = 52 -------(1)
T38 = 128
=> a + 37d = 128 -------(2)
On subtracting equation 1 from 2, we get
19d = 76
=> d = 4
Now,
a + 18(4) = 52
=> a + 72 = 52
=> a = 52 - 72
=> a = - 20
S56 = 56 /2 [ 2(-20) + ( 55)(4)]
= 28 ×( - 40 + 220)
= 28 × 180
= 5040
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